Coulomb force and charge equilibrium on the xy-plane

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SUMMARY

The discussion centers on determining the position and magnitude of a third charge, Q, that achieves charge equilibrium among two point charges, q and 4q, located on the xy-plane. The user calculated R as (2r1 + r2)/3 and Q as 4q/9. However, it was established that Q must be negative to ensure that the forces on charges q and 4q are balanced, leading to the conclusion that Q should be -4q/9. The correct position for Q remains R = (2r1 + r2)/3.

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  • Coulomb's Law for calculating electrostatic forces
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  • Understanding of charge equilibrium in electrostatics
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PRASHANT KUMAR
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Homework Statement


Two point charges q and 4q are located at r1 and r2, respectively, on the xy- plane. The magnitude Q and location R of a third charge to be places on the plane such that the total force on each of the three charges vanishes, are?

first i plotted the problem on the xy coordinate system and then the position vectors of two charges q and 4q as r1 and r2 and then i kept the charge Q at R and then i calculated the sum of forces on the charge q by the two other charges and equated to zero. And again using coulomb force relation i equated the sum of forces on charge Q by q and 4q then i calculated the values of Q and R

i am getting R=(2r1+r2)/3 and Q= 4q/9 but the options are
  1. Q= -4q/9 and R= (2r1+r2)/3
  2. Q= -4q/5 and R= (r1+2r2)/3
  3. Q= -4q/25 and R= (16r1+r2)/17^(1/2)
4.Q= -9q/4 and R =(r1 + 2r2)/3

in calculating the above problem i was equating the magnitude of the forces .
So, is my answer correct or not?
if not then how to calculate that ?
 
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PRASHANT KUMAR said:
am getting R=(2r1+r2)/3 and Q= 4q/9
It clearly cannot have the same sign as q. That would subject q and 4q to net forces pushing them away from Q. Please post your working.
 

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