Coulomb Gauge invariance, properties of Lambda

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SUMMARY

The discussion focuses on the properties that the function Lambda (\Lambda) must satisfy to maintain the Coulomb Gauge condition, defined as \nabla\cdot\vec{A}=0. The analysis reveals that \Lambda must satisfy the wave equation, expressed as \frac{1}{c^{2}}\frac{\partial^{2}\Lambda}{\partial t^{2}}-\nabla^{2}\Lambda=0, to ensure both vector potentials \vec{A} and \vec{A'} comply with the Coulomb Gauge. Participants emphasize the importance of isolating \Lambda in the context of gauge transformations and its implications on the invariance of the fields.

PREREQUISITES
  • Understanding of gauge transformations in electromagnetism
  • Familiarity with the Coulomb Gauge condition
  • Knowledge of wave equations in physics
  • Basic concepts of vector calculus
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  • Study the implications of the Lorentz Gauge Condition on electromagnetic fields
  • Explore the mathematical derivation of the wave equation
  • Investigate the role of gauge invariance in quantum field theory
  • Learn about the physical significance of vector potentials in electromagnetism
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Students and researchers in theoretical physics, particularly those focusing on electromagnetism and gauge theories, will benefit from this discussion.

tylerscott
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Homework Statement


A gauge transformation is defined so as to leave the fields invariant. The gauge transformations are such that \vec{A}=\vec{A'}+\nabla\Lambda and \Phi=\Phi'-\frac{\partial\Lambda}{\partial t}. Consider the Coulomb Gauge \nabla\cdot\vec{A}=0. Find out what properties the function \Lambda must satisfy in order for the Coulomb Gauge to be satisfied.

Homework Equations


Lorentz Gauge Condition
\nabla\vec{A}+\frac{1}{c^{2}}\frac{\partial\Phi}{\partial t}=0

The Attempt at a Solution


\nabla\cdot\vec{A}=\nabla\left(\vec{A'}+\nabla\Lambda\right)=0
\nabla\cdot\vec{A'}+\nabla^{2}\Lambda=0
so
\nabla\cdot\vec{A'}+\nabla^{2}\Lambda+\frac{1}{c^{2}}\frac{\partial }{\partial t}(\Phi'-\frac{\partial\Lambda}{\partial t})=0
and
\nabla\cdot\vec{A'}+\frac{1}{c^{2}}\frac{\partial\Phi'}{\partial t}=\frac{1}{c^{2}}\frac{\partial^{2}\Lambda}{\partial t^{2}}-\nabla^{2}\Lambda

So in order for these to be invariant, \frac{1}{c^{2}}\frac{\partial^{2}\Lambda}{\partial t^{2}}-\nabla^{2}\Lambda=0

So \Lambda must satisfy wave equation.

Now, I feel like I'm missing some of the properties of the gauge, so any help into more insight into \Lambda would be appreciated.
 
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You shouldn't be solving for the Lorentz gauge. The question only mentions the Coulomb gauge. That is the one you need to satisfy. The question says:
\vec{A}=\vec{A'}+\nabla\Lambda
So from here, if you want both A and A' to satisfy the Coulomb gauge, then what does that tell you about lambda? (I'll admit, the question wasn't very specific about what it was asking for).
 
I don't think I understand what that tells me about lambda... More insight please? Haha
 
If a general vector V is going to satisfy the Coulomb gauge, then you need:
\nabla \cdot \vec{V} = 0
right, and the question is saying that it wants both A and A' to satisfy the Coulomb gauge. Also they give you the equation:
\vec{A}=\vec{A'}+\nabla\Lambda
So using the given information, can you get an equation that contains only lambda (not A or A').
 

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