Coulomb Gauge invariance, properties of Lambda

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Homework Help Overview

The discussion revolves around gauge transformations in electromagnetism, specifically focusing on the Coulomb Gauge condition where the divergence of the vector potential \(\vec{A}\) must equal zero. Participants are exploring the properties that the function \(\Lambda\) must satisfy to maintain this gauge condition.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the implications of the gauge transformation equations and how they relate to the Coulomb Gauge. There is an attempt to derive conditions on \(\Lambda\) based on the requirement that both \(\vec{A}\) and \(\vec{A'}\) satisfy the Coulomb Gauge. Questions arise regarding the specific properties of \(\Lambda\) and how to isolate it in the context of the given equations.

Discussion Status

The conversation is ongoing, with some participants seeking clarification on the relationship between \(\Lambda\) and the Coulomb Gauge. There is recognition that the original poster's approach may need adjustment to focus solely on the Coulomb Gauge rather than the Lorentz gauge. Participants are actively engaging with the problem and prompting further exploration of the properties of \(\Lambda\).

Contextual Notes

There is a noted ambiguity in the original question regarding the specific properties of \(\Lambda\) that need to be addressed. Participants are working within the constraints of the problem as stated, which may not provide all necessary details for a complete analysis.

tylerscott
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Homework Statement


A gauge transformation is defined so as to leave the fields invariant. The gauge transformations are such that \vec{A}=\vec{A'}+\nabla\Lambda and \Phi=\Phi'-\frac{\partial\Lambda}{\partial t}. Consider the Coulomb Gauge \nabla\cdot\vec{A}=0. Find out what properties the function \Lambda must satisfy in order for the Coulomb Gauge to be satisfied.

Homework Equations


Lorentz Gauge Condition
\nabla\vec{A}+\frac{1}{c^{2}}\frac{\partial\Phi}{\partial t}=0

The Attempt at a Solution


\nabla\cdot\vec{A}=\nabla\left(\vec{A'}+\nabla\Lambda\right)=0
\nabla\cdot\vec{A'}+\nabla^{2}\Lambda=0
so
\nabla\cdot\vec{A'}+\nabla^{2}\Lambda+\frac{1}{c^{2}}\frac{\partial }{\partial t}(\Phi'-\frac{\partial\Lambda}{\partial t})=0
and
\nabla\cdot\vec{A'}+\frac{1}{c^{2}}\frac{\partial\Phi'}{\partial t}=\frac{1}{c^{2}}\frac{\partial^{2}\Lambda}{\partial t^{2}}-\nabla^{2}\Lambda

So in order for these to be invariant, \frac{1}{c^{2}}\frac{\partial^{2}\Lambda}{\partial t^{2}}-\nabla^{2}\Lambda=0

So \Lambda must satisfy wave equation.

Now, I feel like I'm missing some of the properties of the gauge, so any help into more insight into \Lambda would be appreciated.
 
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You shouldn't be solving for the Lorentz gauge. The question only mentions the Coulomb gauge. That is the one you need to satisfy. The question says:
\vec{A}=\vec{A'}+\nabla\Lambda
So from here, if you want both A and A' to satisfy the Coulomb gauge, then what does that tell you about lambda? (I'll admit, the question wasn't very specific about what it was asking for).
 
I don't think I understand what that tells me about lambda... More insight please? Haha
 
If a general vector V is going to satisfy the Coulomb gauge, then you need:
\nabla \cdot \vec{V} = 0
right, and the question is saying that it wants both A and A' to satisfy the Coulomb gauge. Also they give you the equation:
\vec{A}=\vec{A'}+\nabla\Lambda
So using the given information, can you get an equation that contains only lambda (not A or A').
 

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