Counting Game - A Fun Forum Word Game

[JasonRox]

The posts are already being counted.

 

[scott1]

one minutes ago

 

[mattmns]

one minutes ago

huh?


fünfzehn

 

[scott1]

huh?

$$18:18-18:17 =1$$

 

[mattmns]

OK, but you were supposed to do number 15.

 

[Rach3]

Can't you people count?

 

[scott1]

Can't you people count?

The estimated amount of PFers that can't count.

 

[Mattara]

The correct number in line is:

5

 

[VietDao29]

The correct number in line is:

5

Nah, nah, it's 16.
$$5 = e ^ {i \pi} + 3!$$, as already proposed by mattmns.
-------------
$$16 = \sum_{n = 1} ^ 5 (n) - e ^ {i \pi}$$

 

[Mattara]

6

Come on guys, stick to the rules -_-

 

[scott1]

7 more days of the month

 

[scott1]

6

Come on guys, stick to the rules -_-

Wait is this game only
1
2
3
4
5
6
7
8
9
10
etc.
Then the rules should chaged this theard would no fun if it was like that.

 

[heartless]

I vote for new rules!
New game:
One may start with any number he/she wants, the next person is to add another number making some kind of geometric/arithmetic/sequential pattern, person who adds a number that doesn't belong to the pattern, loses and is disallowed to participate until the next game. I think it would be more fun.
What do you think?

 

[Mattara]

The next number is:

8

heartless: start your own thread. Thank you.

 

[scott1]

I vote for new rules!
New game:
One may start with any number he/she wants, the next person is to add another number making some kind of geometric/arithmetic/sequential pattern, person who adds a number that doesn't belong to the pattern, loses and is disallowed to participate until the next game. I think it would be more fun.
What do you think?

I agree just counting natuarl numbers is boring.
:zzz:

10001

 

[Greg825]

Hurray! Moving on:

$$\left(e^{3}\right)^{\ln 3}$$

=27 does it not?

quick, change it to e^2!

------------------------------

xth prime where x is the nth prime where n is the first prime raised to the first prime.

 

[Mattara]

9

Hint: The next number is 10 in a non-mathematical non-equation

 

[mattmns]

Yep Rach was wrong, and he was complaining about us? I think it is too late to switch it back! I guess we have to go back to 9, our 9 that is, not Mattara's 9.

$$(e^2)^{ln3}$$

To be lazy

 

[VietDao29]

9

Hint: The next number is 10 in a non-mathematical non-equation

Nah, just counting in natural numbers is boring... Let's continue:
$$\prod_{i = 1} ^ 3 (i) - 4 e ^ {i \pi} = 10$$

 

[Chi Meson]

so is 11 next?

In base 3, it's:

102.

 

[scott1]

C
10 character limit

 

[heartless]

$$14_8$$ base 8

 

[scott1]

17 base undeclasifed

 

[heartless]

17 base undeclasifed

Hey, this doesn't count! no 17 of base n equals 13 of base 10 !

 

[scott1]

Ok I used octal

 

[heartless]

I'm wrong
Didn't notice C, sorry. I don't talk anymore.

 

[enigma]

I hate to be the wet blanket, but Greg hates free word association threads and this is even worse...

We have enough server bloat as it is, so I'm going to lock the thread.

Sorry.