Counting problem involving numbered cards

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SUMMARY

The discussion focuses on solving a combinatorial problem involving nine numbered cards: 1, 2, 2, 3, 3, 4, 6, 6, 6. The specific task is to determine how many unique 3-digit numbers can be formed using these cards, constrained to the range of 200 to 300. The solution involves systematically listing the valid combinations, resulting in a total of 22 distinct numbers that meet the criteria.

PREREQUISITES
  • Understanding of combinatorial mathematics
  • Familiarity with permutations and combinations
  • Basic knowledge of number formation and constraints
  • Ability to analyze and list outcomes systematically
NEXT STEPS
  • Study combinatorial counting principles in depth
  • Learn about permutations with repetition
  • Explore constraints in combinatorial problems
  • Practice similar problems involving card or number arrangements
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This discussion is beneficial for students in mathematics, educators teaching combinatorial concepts, and anyone interested in solving practical counting problems involving permutations and constraints.

Milly
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How to solve ii (b) ? Thanks in advance.
 

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Hello, Milly! :D

I have given your thread a title that briefly describes the posted problem. A title like "Help :/" does not tell anyone viewing the thread listing anything about the nature of the question being asked, and it is assumed that help is being sought.

Can you post what you have tried so far, so that our helpers can see where you are stuck, or where you may be going wrong, and can offer better assistance?

Using good thread titles and showing effort are two of the things we ask from our users, as given in our http://mathhelpboards.com/rules/.
 
I actually tried out by using 5P2 but it didn't work.
 
Hello, Milly!

How to solve ii (b)?

7. Nine cards are numbered: 1, 2, 2, 3, 3, 4, 6, 6, 6.

(ii) Three of the nine cards are chosen and placed in a line,
. . .making a 3-digit number.

Find how many different numbers can be made in this way
(b) if the number is between 200 and 300.
The easiest solution is to simply list them.

. . \begin{array}{ccccc} 212 & 221 & 231 & 241 & 261 \\ 213 & 223 & 232 & 242 & 2 62 \\ 214 & 224 & 233 & 243 & 263 \\ 216 & 226 & 234 & 2 46 & 264 \\ && 236 && 266 \end{array}

Answer: 22
 

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