Coupled Quantum Harmonic Oscillator

Click For Summary
SUMMARY

The discussion focuses on transforming the Hamiltonian of a coupled Quantum Harmonic Oscillator into the sum of two decoupled Hamiltonians. The Hamiltonian is expressed as H = H1 + H2 + qxy, where H1 and H2 represent the individual oscillators, and q is the coupling constant. The user has attempted various methods, including variable transformations and completing the square, but has not succeeded in eliminating the coupling term. The solution involves using a rotation of the coordinates instead of completing the square to achieve decoupling.

PREREQUISITES
  • Understanding of Quantum Mechanics principles
  • Familiarity with Hamiltonian mechanics
  • Knowledge of coordinate transformations
  • Experience with coupled oscillators
NEXT STEPS
  • Research coordinate rotation techniques in Quantum Mechanics
  • Study the method of completing the square in Hamiltonian systems
  • Explore examples of decoupling coupled oscillators
  • Learn about the implications of coupling constants in oscillatory systems
USEFUL FOR

This discussion is beneficial for physics students, quantum mechanics researchers, and anyone studying coupled oscillators in theoretical physics.

stumpedstuden
Messages
1
Reaction score
0

Homework Statement


I need to transform the Hamiltonian of a coupled Harmonic Oscillator into the sum of two decoupled Hamiltonians (non-interacting oscillators).


Homework Equations


H = H1 + H2 + qxy, where H1=0.5*m*omega^2*x^2+0.5m^-1P_x^2 and H2=0.5*m*omega^2*y^2+0.5m^-1P_y^2, and q is the coupling constant


The Attempt at a Solution


I have tried a number of variable transformations, etc as well as attempted to complete the square to deive the proper variables that will allow me to rewrite the Hamiltonian properly. All without success. I thought completing the square and making the proper substitions would work but I still end up with a coupled term. Once this step is complete solviing the rest of the problem should be pretty straightforward.

Any help that gets me started would be greatly appreciated.
 
Physics news on Phys.org
To get rid of the cross term, you don't want to complete the square; you need to use a rotation of the coordinates.
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 2 ·
Replies
2
Views
4K
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
1
Views
2K