- 128

- 0

a|n> = √n | √(n-1)>

and

a' |n> = √(n+1) | n + 1 >

so, If we use this to find

<n|a'a|n>

it would be equal to n

<n|a'a|n> = n

Am I correct?

I'm not really sure about my calculations.

I operate with a first so.

<n|a'a|n>

<n|a' √n | √(n-1)>

= n

????

Can someone please help me with the complete solution?