- #51

- 36

- 0

oh sure .. [tex]y=\frac{z-1}{z+1}x[/tex]

with z in (1,+oo)

[PLAIN]http://img525.imageshack.us/img525/2809/unoj.jpg [Broken]

if (z->+oo) ==> [tex]F_z(z)=\int_{0}^{1}xdx=0.5[/tex]

if z=1 ==>[tex]F_z(z)=\int_{0}^{0}1dx=0[/tex]

[tex]F_z(z)=\int_{0}^{1}\frac{z-1}{z+1}dx=\frac{z-1}{2(z+1)}[/tex]

with z in (-oo,-1)

[PLAIN]http://img689.imageshack.us/img689/4300/duex0.jpg [Broken]

[tex]F_z(z)=\int_{0}^{1}\frac{z+1}{z-1}dy=\frac{z+1}{2(z-1)}[/tex]

if (z->-oo) ==>[tex]F_z(z)=\int_{0}^{1}ydy=0.5[/tex]

if z=-1 ==>[tex]F_z(z)=1[/tex] because y->+oo

with z in (1,+oo)

[PLAIN]http://img525.imageshack.us/img525/2809/unoj.jpg [Broken]

if (z->+oo) ==> [tex]F_z(z)=\int_{0}^{1}xdx=0.5[/tex]

if z=1 ==>[tex]F_z(z)=\int_{0}^{0}1dx=0[/tex]

[tex]F_z(z)=\int_{0}^{1}\frac{z-1}{z+1}dx=\frac{z-1}{2(z+1)}[/tex]

with z in (-oo,-1)

[PLAIN]http://img689.imageshack.us/img689/4300/duex0.jpg [Broken]

[tex]F_z(z)=\int_{0}^{1}\frac{z+1}{z-1}dy=\frac{z+1}{2(z-1)}[/tex]

if (z->-oo) ==>[tex]F_z(z)=\int_{0}^{1}ydy=0.5[/tex]

if z=-1 ==>[tex]F_z(z)=1[/tex] because y->+oo

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