Current and power with transformers

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An ideal single-phase transformer with a 240V/2880V rating is analyzed, where a 3-ohm resistance cable affects the input voltage. The primary current was calculated to be 80A, but the participant struggled with incorporating the 720-ohm load resistor into their power calculations. It was suggested to transform the 720-ohm load to find its equivalent resistance on the primary side and to use the potential divider method to determine the actual input voltage to the transformer. The correct input voltage was found to be 150V, leading to further clarification on calculating power using the secondary current or voltage. The discussion emphasized the importance of understanding transformer principles and circuit analysis for accurate problem-solving.
Cocoleia
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Homework Statement


I am working on the following problem:

And ideal single phase transformer 240V/2880V is supplied with a 240V source via a resistance cable of 3ohm. If we connect a R=720ohm resistance to this, determine the primary current and the dissipated power in R.
(I'm sorry if some of the wording is wrong, I am translating the question into English ... )

Homework Equations

The Attempt at a Solution


upload_2017-11-8_11-59-49.png

I tried to find the current in 2 different ways, and came to 80A each time.
For the dissipated power, I am really not sure how to incorporate this 720ohm. I read in my notes that Power in = Power out, but I feel like this isn't the answer for this situation..
 

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Not sure I can follow your working. The voltage going into the transformer won't be 240V because some is lost across the 3R cable.

The way I would approach the problem is to "transform" the 720R load resistor to work out what the equivalent load would be on the primary side. Then use the potential divider method to work out the actual input voltage to the transformer.

Edit: If this is confusing start with a circuit diagram.
 
CWatters said:
Not sure I can follow your working. The voltage going into the transformer won't be 240V because some is lost across the 3R cable.

The way I would approach the problem is to "transform" the 720R load resistor to work out what the equivalent load would be on the primary side. Then use the potential divider method to work out the actual input voltage to the transformer.

Edit: If this is confusing start with a circuit diagram.
You mean transform it so everything is on the primary side ? Or how do I transform it ?
 
CWatters said:
Not sure I can follow your working. The voltage going into the transformer won't be 240V because some is lost across the 3R cable.

The way I would approach the problem is to "transform" the 720R load resistor to work out what the equivalent load would be on the primary side. Then use the potential divider method to work out the actual input voltage to the transformer.

Edit: If this is confusing start with a circuit diagram.
If I do this, I get an input voltage of 150V, which I then divide my 3ohm to get my current ?
 
Yes I mean transform it so everything is on the primary side. An example...

Lets say you had a 2:1 step down transformer with a 10R on the secondary side. That 10R would be equivalent to a 40R on the primary side...

Proof...

The secondary current Is = Vs/Rs. If N is the winding ratio the primary current Ip would be Is/N = Vs/NRs.

The equivalent resistance Rp on the primary side = Vp/Ip = Vp/(Vs/NRs) = N2Rs

If N = 2 and Rs = 10 then Rp = 40.
 
Cocoleia said:
If I do this, I get an input voltage of 150V, which I then divide my 3ohm to get my current ?

Yes the input voltage to the transformer is 150V but it's not across the 3R. The voltage across the 3R is 240-150V.
 
A
CWatters said:
Yes the input voltage to the transformer is 150V but it's not across the 3R. The voltage across the 3R is 240-150V.
ah, I see.

would the power then be the secondary current multiplied by 720^2 ?
 
Not 720 squared

You can use Is2*R or Vs2/R
 
CWatters said:
Not 720 squared

You can use Is2*R or Vs2/R
Perfect, thank you !
 

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