Wires A and B, having equal lengths of 40.0 m and equal diameters of 2.60 mm, are connected in series. A potential difference of 60.0 V is applied between the ends of the composite wire. The resistances of the wires are 0.127 and 0.729 , respectively.
(a) the current density in each wire [A/m2]
(b) the potential difference across each wire. [V]
V = iR
The Attempt at a Solution
I found the volume of 1 wire, SA times Length, 2.6 mm diameter is a .0013 m radius, squared times pi yields 5.31 E-6 for the surface area, times the length of 40m is volume of 2.124E-4.
I tried V=iR, but for the first wire I had 60=.127R, which would make the current 472.44, which I'm not sure how to relate to the volume.
I don't know how to find the potential difference either.