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Shelby8
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Homework Statement
An office worker uses an immersion heater to warm 250 g of water in a light, covered, insulated cup from 20 degrees C to 100 degrees C in 4 minutes. The heater is Nichrome resistance wire connected to 120V power supply. Assume wire is at 100 degree C during 4 minute time interval.
a) calculate average power required to warm the water to 100 degree C in 4 min
b) calculate the required resistance in the heating element at 100 degree C
c) calculate the resistance of the heating element at 20 degree C
d) derive a relationship between the diameter of the wire, resistivity at 20 degree C, rou (po), the resistance at 20 degree C, Ro, and the length L
e) If L = 3 m, what is the diameter of the wire?
What we are given:
mass of water = 250 g
density of water = 1000 kg / m^3
change in T = 80
V = 120V
t = 4 minutes
p of Nichrome = 150 *10^-8
coeff of resistivity of Nichrome = 0.4 * 10^-3
Homework Equations
P = I*V = V^2/I = I^2*R
R = V/I
R = Ro [1 + coefficient of resistivity (T - To)]
R = p L / A
I = Q / t
The Attempt at a Solution
a) calculate average power required to warm the water to 100 degree C in 4 min
density = m / v ... v = m / density
v = A * L
v = 250 / 1000 = .25 m ^3 = A * L
R = p L / (.25/L) = p L^2 / .25
How do I calculate I for Power without knowing the charge?