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Homework Statement
Suppose you want to run some apparatus that is 95 m from an electric outlet. Each of the wires connecting your apparatus to the 120 V source has a resistance per unit length of 0.0065 Ω/m. If your apparatus draws 2.9 A, what will be the voltage drop across the connecting wires and what voltage will be applied to your apparatus?
Homework Equations
V=IR
The Attempt at a Solution
For voltage drop:
Rwire=.0065(95)=.6175Ω
V=IR=2.9*.6175=1.79*2(to apparatus and back)=3.58V which was wrong.
I got the answer to what voltage will be applied to your apparatus which was:
Rapparatus=V/I=120/2.9=411.379Ω
Rtotal=Rapp+Rwire=41.379+.6175=41.996Ω
Itot=V/Rtot=12-/42=2.85A
V=ItotRwire=2.85*.6175=1.764V
120V-1.764V=118.23V