Current in a hollowed nichrome wire

[Minhtran1092]

Homework Statement

A 10.0 cm long hollow nichrome tube of inner diameter 2.20 mm , outer diameter 5.10 mm is connected to a 2.50 V battery. What is the current in the tube?

Homework Equations

V=IR
R = p*(L/A);p = resistivity of nichrome (1.5E-6), L = length of wire, A = Surface area of cross section

The Attempt at a Solution

V = I*R → V/R = I; V = 2.5V
R = p*(.1cm)/(π([5.1/2]/1000))²)-π((1.1/1000)²))

I = 2.5/R; Isn't correct

 

[BluFoot]

Looks good to me, you must have done some calculations wrong... If you used wolframalpha or similar, your brackets are wrong so that might have messed it up...

I got R=0.00902 ohms, I=277 A