Current in secondary of transformer

[codems5]

I am trying to get a better understanding of transformers. Assuming the transformer is ideal, and the secondary is connected to a high impedance load such as an oscilloscope, would there essentially be no current in the secondary?

In this case the turn ratio is one. So ideally, the voltages would be equal. However, if there is no current in the secondary, what is happening to the power that is transferred to the secondary? Does it just remain in the magnetic field? Thanks

 

[marcusl]

I am trying to get a better understanding of transformers. Assuming the transformer is ideal, and the secondary is connected to a high impedance load such as an oscilloscope, would there essentially be no current in the secondary?

Correct.

In this case the turn ratio is one.

No, it is still given by the physical turns ratio n.

So ideally, the voltages would be equal.

No, the secondary EMF is V_2=nV_1 as usual. Faraday's law specifies the EMF generated in a loop by changing flux. Secondary current flow depends on load resistance, and may be absent as it is in this case.

However, if there is no current in the secondary, what is happening to the power that is transferred to the secondary? Does it just remain in the magnetic field? Thanks

There is no power transferred to the secondary, so no power drawn by the primary in your case of an ideal lossless transformer.

 

[codems5]

By saying "in this case", I meant the transformer I am working with has a turn ratio of one and thus the voltages would be equal. Sorry for the confusion. However, you answered the rest of my questions. thank you