Curvature implying Closedness in N dimensions

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Discussion Overview

The discussion revolves around the implications of positive curvature on surfaces in various dimensions, particularly whether surfaces with everywhere positive curvature are necessarily closed and isomorphic to spheres or hyperspheres. The conversation includes theoretical considerations and references to specific theorems in differential geometry.

Discussion Character

  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants assert that a two-dimensional surface with everywhere positive curvature is a closed surface isomorphic to a sphere, questioning if this holds for higher dimensions.
  • Others challenge this claim, suggesting that the term "isomorphic" needs clarification and that the statement may not be universally true.
  • A participant references the Stoker-Hadamard theorem, indicating that a closed surface with positive Gaussian curvature is either diffeomorphic to a sphere if compact or to a graph on an open, convex subset of the plane, emphasizing that closure is a hypothesis rather than a conclusion.
  • Another participant corrects the previous claims, stating that while a surface with positive constant curvature is homeomorphic to a sphere, non-closed surfaces can also exhibit positive curvature, citing the example of a paraboloid.
  • One participant argues that the projective plane can have a metric of constant positive Gaussian curvature, highlighting that there exist many surfaces with boundaries that possess positive Gaussian curvature.
  • It is noted that a closed orientable smooth surface without boundary of positive Gaussian curvature must be a sphere, based on the relationship between the integral of Gaussian curvature and the Euler characteristic.

Areas of Agreement / Disagreement

Participants express differing views on the relationship between positive curvature and the closedness of surfaces. There is no consensus on whether the initial claim regarding higher-dimensional surfaces holds true, and multiple competing perspectives are presented.

Contextual Notes

Participants highlight the importance of definitions and theorems in the discussion, with some noting that assumptions about closure and isomorphism are critical to the arguments being made. The conversation reflects a nuanced understanding of the implications of curvature in differential geometry.

jfizzix
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A two-dimensional surface with everywhere positive curvature is a closed surface with no boundary (isomprphic to a sphere).

Is this true for higher dimensional surfaces as well?
Would a three-dimensional surface, with everywhere positive curvature be a closed hypersurface isomorphic to a hypersphere?
 
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jfizzix said:
A two-dimensional surface with everywhere positive curvature is a closed surface with no boundary (isomprphic to a sphere).

Unless you are speaking very loosely, I don't think this is true. What do you mean with "isomorphic" in this case anyway?
 
If you are referring to the Stoker-Hadamard theorem, it states that any closed surface with positive Gaussian curvature is positive everywhere is either
1) Diffeomorphic to the sphere if it is compact
2) Diffeomorphic to the graph on an open, convex subset of the plane.
So the conclusion is not that the surface is closed in ##\mathbb{R}^3##, rather it is one of the hypotheses.
 
I think you are misquoting that theorem. A surface with positive constant curvature is homeomorphic (not "isomorphic") to a sphere, but you can have a non-close surface, such as a paraboloid, that has positive curvature everywhere, going to 0 as the distance from a fixed point goes to infinity.
 
jfizzix said:
A two-dimensional surface with everywhere positive curvature is a closed surface with no boundary (isomprphic to a sphere).

Is this true for higher dimensional surfaces as well?
Would a three-dimensional surface, with everywhere positive curvature be a closed hypersurface isomorphic to a hypersphere?

This is not true for surfaces. One can give the projective plane a metric of constant positive Gauss curvature. There are many surfaces with boundary that have positive Gauss curvature.

A closed orientable smooth surface without boundary of positive Gauss curvature must be a sphere. This is because the integral of the Gauss curvature is 2π time the Euler characteristic and all surfaces other than the sphere have non-positive Euler characteristic.
 
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