Cutting a hollow sphere into 2 piece but not in half

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Homework Help Overview

The problem involves determining the center of mass for a uniform sphere that has been cut into two portions, focusing on a smaller portion with a specified height. The discussion includes locating the center of mass for both the solid and hollow versions of the portion.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss different expressions for the mass of the spherical cap and compare their results. There are attempts to reconcile discrepancies between different parts of the problem, particularly between parts b and c.

Discussion Status

Some participants have shared their calculations and expressed confidence in their results, while others are questioning the differences in their answers. There is an ongoing exploration of the relationships between the different parts of the problem, but no consensus has been reached regarding the correct answers for parts b and c.

Contextual Notes

Participants are working under the constraints of homework guidelines and are attempting to clarify their understanding of the mass expressions and center of mass calculations without providing direct solutions.

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Homework Statement


A uniform sphere of radius R is cut into two portions. The smaller portion S has height h measured from its flat surface, where h<R.

(a) Locate the center of mass of S from its flat surface

(b) Use (a) the locate the centre of mass of a hollow H which has the same shape and same size as S. The hollow has only a thin curved surface and without any flat surface.
(c) Obtain the result of (b) by direct integration.

Homework Equations


This question use 2 tricks to find the center of mass of a hollow.
1. Use substraction to substract a big object by a smaller one and then take limit. (I hope you understand what I mean.)
2. Use direction integration.


The Attempt at a Solution


My answer in part b doesn't agree with part c, can anyone help me to check what happen?
 

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I found a different expression for the mass of the cap:
[tex]m=\frac{\rho\pi h^2(3R-h)}{3}[/tex]
 
vela said:
I found a different expression for the mass of the cap:
[tex]m=\frac{\rho\pi h^2(3R-h)}{3}[/tex]

In fact I have same expression as you
[itex]\frac{h^{3}}{3}[/itex]-[itex]h^{2}R[/itex]

But when I copy it form messy worksheet to a much neat writting, I try to simplfy the expression in my mind, unforunately, I fail:-p

So my expression for the mass is also correct.
 
Last edited:
Did you get it to work out?
 
vela said:
Did you get it to work out?

Yes, of course.
I do this question with 2 other classmates, we check a hundred time for our answer. I am sure we get it correct.
 
so may i ask for b) and c)

the ans is..h/2 or h(4R-4) / 3(3R-h)

cuz my ans is not same as yours...

btw where the ans for b and c are not the same
 
The answers you get for b and c should both be h/2.
 
tim94131358 said:
so may i ask for b) and c)

the ans is..h/2 or h(4R-4) / 3(3R-h)

cuz my ans is not same as yours...

btw where the ans for b and c are not the same

what do you get?
 

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