D2sp3 and sp3d2 Configurations of [Cr(NH3)6]3+ Ligand Complex

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Discussion Overview

The discussion centers on the electronic configuration and hybridization of the chromium ion in the complex [Cr(NH3)6]3+, specifically exploring whether the hybridization is d2sp3 or sp3d2. Participants examine the implications of weak field ligands and the electron donation process from the ligands.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant states that the configuration of Cr3+ is 3d3,4s0 and questions whether ligands will donate electrons starting from 3d or from 4s, 4p, and 4d orbitals.
  • Another participant suggests that opening up a new 4d for hybridization is energy consuming and non-stabilizing.
  • Some participants assert that the hybridization is d2sp3, noting that the eg orbitals will be filled with electrons from ligands while the t2g orbitals will remain partly filled with the metal's electrons.
  • One participant emphasizes that the t2g being partly filled implies that the complex would be paramagnetic and suggests applying concepts of valence bond theory in crystal field theory (CFT).

Areas of Agreement / Disagreement

Participants generally agree on the d2sp3 hybridization but there is ongoing debate regarding the specifics of electron donation and the implications for the electronic structure of the complex.

Contextual Notes

There are unresolved questions regarding the energy implications of hybridization and the specific roles of the 4d orbitals in the hybridization process.

AdityaDev
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[Cr(NH3)6]3+ has Cr3+ ion and the ligand is weak field.
Hence the configuration of Cr ion is 3d3,4s0
My doubt is,will the ligands donate electrons starting from 3d to form d2sp3 or will it start from 4s and use 4p and 4d to form sp3d2?
I know the 3 electrons of chromium are still unpaired but that d orbital can accommodate 2 pairs of electrons.
 
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opening up a new 4d for hybridization, is energy consuming, and non stabilizing, isn't it?
 
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So its d2sp3 then. But you will have the eg orbitals filled with electrons from ligands and the t2g partly filled by the metal's electrons.
 
AdityaDev said:
So its d2sp3 then. But you will have the eg orbitals filled with electrons from ligands and the t2g partly filled by the metal's electrons.
Yes, it's d2sp3. Yes t2g will remain partly filled and that implies it would be paramagnetic. Applying some of the concepts of valence bond theory in CFT could be useful.
 
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