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Bonding in coordination complexes

  1. Oct 29, 2013 #1
    For metals like copper(I), how does it have a coordination number of 3 in some compounds like [Cu(P(C6H5)3)3]+. I've learned that these coordination bonds are formed by interacting lone pairs from ligands and empty orbitals on the central metal atom. In this case, copper has a 1+ charge and configuration of [Ar] 4s0 3d10 and I'm just slightly confused on how it would form 3 bonds...
    Would new bonds just be formed between the lone pair on each phosphorous and the 3 4p orbitals from copper? What happens to the 4s orbital in this case?

    If there's a method to determine the coordination number of a metal with ligands, could you please expand on that as well or refer me to any sources?

  2. jcsd
  3. Dec 14, 2013 #2
    Is this question not addressed by CTF?
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