- #1
lekh2003
Gold Member
- 539
- 342
I've been attempting to run through some quantum mechanics and I've seen something extremely odd, and I just can't spot my mistake.
I know the relationships: ##p = \frac{h}{\lambda}## and ##E = hf##. I also know the relationship ##E = \frac{p^2}{2m}##.
I tried to show using the energy-momentum relation and the de Broglie wavelength equation that ##E = hf## is true, but its simply inconsistent.
\begin{align}
E &= \frac{p^2}{2m}\\
&= \frac{(\frac{h}{\lambda})^2}{2m}\\
&= \frac{(\frac{hf}{v})^2}{2m}\\
&= \frac{\frac{E^2}{v^2}}{2m}\\
&= \frac{E^2}{2mv^2}\\
&= \frac{E^2}{2(\frac{h}{\lambda})v}\\
&= \frac{E^2}{2E}\\
&= \frac{E}{2}
\end{align}
Where am I messing this up?
I know the relationships: ##p = \frac{h}{\lambda}## and ##E = hf##. I also know the relationship ##E = \frac{p^2}{2m}##.
I tried to show using the energy-momentum relation and the de Broglie wavelength equation that ##E = hf## is true, but its simply inconsistent.
\begin{align}
E &= \frac{p^2}{2m}\\
&= \frac{(\frac{h}{\lambda})^2}{2m}\\
&= \frac{(\frac{hf}{v})^2}{2m}\\
&= \frac{\frac{E^2}{v^2}}{2m}\\
&= \frac{E^2}{2mv^2}\\
&= \frac{E^2}{2(\frac{h}{\lambda})v}\\
&= \frac{E^2}{2E}\\
&= \frac{E}{2}
\end{align}
Where am I messing this up?