De Broglie Relations Confusion

In summary, the conversation revolves around a mistake in using the energy-momentum relation and the de Broglie wavelength equation to show that E=hf is true. The mistake was caused by using the phase velocity instead of the group velocity in the dispersion relation. The correct dispersion relation for free Schrödinger waves is provided and the topology of spacetime is discussed. The conversation ends with a comment unrelated to the initial topic.
  • #1
lekh2003
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I've been attempting to run through some quantum mechanics and I've seen something extremely odd, and I just can't spot my mistake.

I know the relationships: ##p = \frac{h}{\lambda}## and ##E = hf##. I also know the relationship ##E = \frac{p^2}{2m}##.

I tried to show using the energy-momentum relation and the de Broglie wavelength equation that ##E = hf## is true, but its simply inconsistent.

\begin{align}
E &= \frac{p^2}{2m}\\
&= \frac{(\frac{h}{\lambda})^2}{2m}\\
&= \frac{(\frac{hf}{v})^2}{2m}\\
&= \frac{\frac{E^2}{v^2}}{2m}\\
&= \frac{E^2}{2mv^2}\\
&= \frac{E^2}{2(\frac{h}{\lambda})v}\\
&= \frac{E^2}{2E}\\
&= \frac{E}{2}
\end{align}

Where am I messing this up?
 
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  • #2
You've used the phase velocity: ##v_p = f\lambda = \frac{v}{2}##.

In the de Broglie mechanics it's the group velocity that is the velocity of the particle: ##v_g = v##.
 
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  • #3
Thank you so much! Everything makes sense now, I read up some more on a StackExchange thread.
 
  • #4
In other words you need to use the correct dispersion relation for free Schrödinger waves, which results from
$$E=\hbar \omega = \frac{p^2}{2m}=\frac{(\hbar k)^2}{2m},$$
i.e.,
$$\omega = \frac{\hbar}{2m} k^2.$$
In your notation it's
$$2 \pi f=\frac{h}{4 \pi m} \frac{(2 \pi)^2}{\lambda^2} \; \Rightarrow \; f=\frac{h}{2m \lambda^2}.$$
 
  • #5
The neighborhood of an event includes points that are timelike, null, and spacelike separated from it; the light cone does not bound the neighborhood. The topology of spacetime is still ##R^4## even though the metric on it is not the one induced by that topology. Thanks
 
  • #6
iosman001 said:
The neighborhood of an event includes points that are timelike, null, and spacelike separated from it; the light cone does not bound the neighborhood. The topology of spacetime is still ##R^4## even though the metric on it is not the one induced by that topology. Thanks
Did you attach this post to the wrong thread? It looks off-topic here.
 
  • #7
iosman001 said:
The neighborhood of an event includes points that are timelike, null and spacelike separated from it; the light cone does not bound the neighborhood. The topology of spacetime is still R4R4R^4 even though the metric on it is not the one induced by that topologyhttps://chatavenue.vipThanks

thanks my issue has been fixed.
 
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