Dealing with 5 input variable Kmaps

  • Context: MHB 
  • Thread starter Thread starter shamieh
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SUMMARY

This discussion focuses on solving a 5-input Karnaugh map (K-map) for the function f(V,W,Z,Y,Z) to derive the minimal Sum of Products (SOP) equation. The K-map is structured with WX as the column variables and YZ as the row variables. The user presents their solution as $$vzw + zw\bar{x} +\bar{v}\bar{y}z\bar{w}$$, seeking validation of their work. The K-map analysis reveals the correct grouping and simplification of terms for optimal logic expression.

PREREQUISITES
  • Understanding of Karnaugh maps (K-maps)
  • Familiarity with Boolean algebra
  • Knowledge of Sum of Products (SOP) form
  • Basic logic circuit design principles
NEXT STEPS
  • Study advanced K-map techniques for more than 5 variables
  • Learn about Quine-McCluskey algorithm for Boolean function minimization
  • Explore software tools for K-map simplification, such as Logisim
  • Research practical applications of K-maps in digital circuit design
USEFUL FOR

This discussion is beneficial for electrical engineering students, digital logic designers, and anyone involved in optimizing Boolean expressions for circuit design.

shamieh
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Just need someone to check my work. Thank you for your time. First time doing a 5 input Kmap.

Determine the following 5 input Karnaugh map for function f(V,W,Z,Y,Z) determine the minimal SOP equation. NOTE: (WX are the variables associated with the top column, and YZ are the variables associated with the other column horizontally.)

[TABLE="class: grid, width: 250"]
[TR]
[TD]YZ|WX
[/TD]
[TD]00
[/TD]
[TD]01
[/TD]
[TD]11
[/TD]
[TD]10
[/TD]
[/TR]
[TR]
[TD]00
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[/TR]
[TR]
[TD]01
[/TD]
[TD]1
[/TD]
[TD]1
[/TD]
[TD]0
[/TD]
[TD]1
[/TD]
[/TR]
[TR]
[TD]11
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]1
[/TD]
[/TR]
[TR]
[TD]10
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[/TR]
[/TABLE]
v = 0

[TABLE="class: grid, width: 250"]
[TR]
[TD]YZ|WX
[/TD]
[TD]00
[/TD]
[TD]01
[/TD]
[TD]11
[/TD]
[TD]10
[/TD]
[/TR]
[TR]
[TD]00
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[/TR]
[TR]
[TD]01
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]1
[/TD]
[TD]1
[/TD]
[/TR]
[TR]
[TD]11
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]1
[/TD]
[TD]1
[/TD]
[/TR]
[TR]
[TD]10
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[TD]0
[/TD]
[/TR]
[/TABLE]
v = 1

My Answer: $$vzw + zw\bar{x} +\bar{v}\bar{y}z\bar{w}$$
 
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Looks good to me.
 

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