Decay into an electron and an electron-anti-neutrino?

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SUMMARY

The decay of a pion (\(\pi^-\)) into a muon (\(\mu^-\)) and a muon anti-neutrino (\(\bar{\nu_\mu}\)) is favored over the decay into an electron and an electron anti-neutrino due to helicity conservation principles. The pion, having spin zero, requires the decay products to have matching helicities, while the Vector-Axial (V-A) theory of weak interactions promotes opposite helicities. This results in a significant suppression of the decay channel involving electrons, with a decay rate ratio of approximately \(10^{-4}\) compared to the muon decay channel, influenced by the mass ratio factor \((m_e/m_\mu)^2.

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\pi ^- \rightarrow \mu^- +\bar{\nu_\mu}

Why doesn't it decay into an electron and an electron-anti-neutrino? I guess it has something to do with the conservation of the helicity. But how does it work?
 
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The pi-->e nu decay occurs but at about 10^-4 compared to the mu decay channel. Helicity is involved. Because the pi has spin zero, the two decay particles have to have the same helicity (giving total S_z=0). But the V-A theory of weak interactions tries to give them opposite helicities. This mismatch leads to a factor (m_e/m_mu)^2 in the ratio of e to mu decay.
 

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