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Deceleration Vs time and distance

  1. Apr 17, 2010 #1
    An object decelerates from 20 m s to 10 m s. Deceleration is a constant 2.50 m s−2.

    Firstly, time taken. change in speed over deceleration? Would make it 4 seconds. Is that correct?

    Secondly how do I calculate the distance covered? Is it simply change in speed x time
    which would make it 40 m? Or is it more complicated than this?
     
  2. jcsd
  3. Apr 18, 2010 #2
    No. Distance is velocity times time elapsed(and not change in velocity). Since velocity changes you should integrate for distance.
     
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