Deceleration Vs time and distance

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SUMMARY

An object decelerates from 20 m/s to 10 m/s with a constant deceleration of 2.50 m/s². The time taken for this deceleration is 4 seconds, calculated using the formula for time as the change in speed divided by deceleration. To calculate the distance covered during this deceleration, one must integrate the velocity over time rather than simply multiplying the change in speed by time, resulting in a more accurate distance calculation.

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An object decelerates from 20 m s to 10 m s. Deceleration is a constant 2.50 m s−2.

Firstly, time taken. change in speed over deceleration? Would make it 4 seconds. Is that correct?

Secondly how do I calculate the distance covered? Is it simply change in speed x time
which would make it 40 m? Or is it more complicated than this?
 
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No. Distance is velocity times time elapsed(and not change in velocity). Since velocity changes you should integrate for distance.
 

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