Define Vector on x-Axis: -d/2 to d/2

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The discussion clarifies how to define a vector on the x-Axis from -d/2 to d/2. The vector is represented as ##(d)##, indicating its length. To specify both the point of application and the vector's direction, the notation ##(p;\vec{v})## is used, resulting in ##(p;\vec{v})=(-\frac{d}{2};d)##. This notation effectively communicates the vector's starting point and its magnitude along the x-Axis.

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How do I define a vector starting on the x-Axis at -d/2 ending at d/2 on the x-Axis?
 
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Philosophaie said:
How do I define a vector starting on the x-Axis at -d/2 ending at d/2 on the x-Axis?
You define it as ##(d)##.

A vector notation doesn't say anything about where it is applied at. It simply has a length - here ##d## - and a direction - here only in one coordinate, so ##(*)\,##. If you want to describe a vector as its point of application and its length and direction, then you need to use pairs ##(p;\vec{v})##. Here it would be ##(p;\vec{v})=(-\frac{d}{2};d)##.
 

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