Limit of y/(1-x) as x approaches 1 in a triangular region

[daudaudaudau]

If I define a triangle like this

$$0\le y\le 1$$ and $$0\le x\le 1-y$$,

then what is

$$\lim_{x\rightarrow 1} \frac{y}{1-x}$$ ?

As far as I can see, there are many possibilities, depending on how you "approach" $$x=1$$.

 

[HallsofIvy]

What you are writing doesn't make sense. Since you are taking the limit only as x goes to 1, y is some fixed number between 0 and 1. If $x\le 1-y$ and y is not 1 then x cannot "approach" 1. If y= 1, then, of course, the limit does not exist.

 

[daudaudaudau]

Hmm, yeah, maybe it does not make much sense. Fortunately, I was able to fix my problem in another way, which gave a result with no singularities. So I don't have to solve this problem :) Phew.