How Does the Delta Function and Its Derivative Interact with Shifted Functions?

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SUMMARY

The discussion focuses on the interaction between the delta function and its derivative with shifted functions, specifically proving the relationship ∫-∞∞δ'(x)*f(x-a) = -f'(a). The proof utilizes integration by parts and the integral definition of the delta function, demonstrating that ∫-∞∞δ'(x)*f(x-a) can be expressed as f(-a) - f'(-a). This establishes a clear connection between the delta function's properties and the behavior of shifted functions.

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  • Understanding of the delta function and its properties
  • Familiarity with integration by parts
  • Knowledge of shifted functions in calculus
  • Basic concepts of functional analysis
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Students and professionals in mathematics, physics, and engineering who are working with distributions, particularly those interested in the applications of the delta function and its derivatives in various fields.

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Homework Statement


Prove the following
'()( − ) = −′()
-∞δ'(x)*f(x-a) = -f'(a)

Homework Equations


-∞δ'(x-a)*f(x) = f(a)

The Attempt at a Solution


[/B]
-∞ δ'(x)*f(x-a) = ∫δ(x)*f(x-a)dx-∫f'(x-a)*δ(x)dx = f(-a) - f'(-a)
Went from 1st to second by integration by parts
Used integral definition of delta function to go to 3rd part
 

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The Attempt at a Solution



1) ∫-∞ ∞δ'(x)*f(x-a)
2) = ∫δ(x)*f(x-a)dx-∫f'(x-a)*δ(x)dx
3) = f(-a) - f'(-a)
Went from 1st to second by integration by parts
Used integral definition of delta function to go to 3rd part

Made above easier to read
 

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