I Delta sequence "extrapolation"

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The discussion centers on the properties of delta sequences, specifically whether the function φ_n(x) qualifies as a delta sequence due to its sifting property. It is confirmed that φ_n(x) exhibits the expected behavior of a delta function, allowing it to be used in testing other sifting properties for various arguments. The confusion arises from the semantics of applying φ_n to different inputs while maintaining the sifting property. The conversation emphasizes the importance of understanding how φ_n(x) can represent the delta function for shifted arguments. Overall, the participants seek clarity on the theoretical implications of these properties in the context of distribution functions.
Elm8429
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Studying delta sequences and am wondering if ##\phi_n(x)## is a delta sequence, does it extends that property to all of it's arguments ?
Studying delta sequences and am wondering if ##\phi_n(x)## is a delta sequence (it resembles and validates the sifting property), will ##\phi_n(x - a)## or ##\phi_n(whatever)## respect the sifting property ? I think I get confused in the semantics, because reading my textbook, I get the following where I test if ##\phi_n(x)## is a delta sequence if it has the expected sifting property of the delta function, but then we use ##\phi_n(x)## to test all the other sifting properties of the delta function for different arguments ! : we confirmed that ##\phi_n(x)## is a delta sequence, so ##\phi_n(whatever)## can express the delta function of ##\delta(whatever)## the get "whatever" shifting property.

I hope my confusion was clear and that someone will remedy my theoretical woes !
 
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Though I do not know the context, say distribution function for continuous variable x
\phi_n(x)=\delta(x-a_n),
\int f(x) \phi_n(x)dx =f(a_n)
for any f(x).
 
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