- #1
ebol
- 6
- 0
Hi!
I have to show that
[itex] [L_i,x_j]= i \hbar \varepsilon_{ijk} x_k [/itex]
but my result is different, I'm definitely making a mistake
ok I wrote
[itex] L_i = \varepsilon_{ijk} x_j p_k [/itex]
then
[itex] [L_i,x_l]= \varepsilon_{ijk} ( [x_j p_k , x_l] ) = \varepsilon_{ijk} ( {x_j [p_k , x_l] + [x_j , x_l] p_k } ) = \varepsilon_{ijk} ( {x_j [p_k , x_l] } ) = [/itex]
[itex] = \varepsilon_{ijk} ( {x_j \frac{\hbar}{i} δ_{kl} } ) = \frac{\hbar}{i} \varepsilon_{ijk} {x_j } [/itex]
can anyone tell me where I'm wrong?
thanks anyway!
I have to show that
[itex] [L_i,x_j]= i \hbar \varepsilon_{ijk} x_k [/itex]
but my result is different, I'm definitely making a mistake
ok I wrote
[itex] L_i = \varepsilon_{ijk} x_j p_k [/itex]
then
[itex] [L_i,x_l]= \varepsilon_{ijk} ( [x_j p_k , x_l] ) = \varepsilon_{ijk} ( {x_j [p_k , x_l] + [x_j , x_l] p_k } ) = \varepsilon_{ijk} ( {x_j [p_k , x_l] } ) = [/itex]
[itex] = \varepsilon_{ijk} ( {x_j \frac{\hbar}{i} δ_{kl} } ) = \frac{\hbar}{i} \varepsilon_{ijk} {x_j } [/itex]
can anyone tell me where I'm wrong?
thanks anyway!