Derivation of a formula with trigonometric functions

1. Mar 2, 2012

j1221

Hi everyone,

1. The problem statement, all variables and given/known data

My problem is just to derive a simple formula, which is

http://www.texify.com/img/%5Cnormalsize%5C%21%28-1%29%5E%7Br%28r%2B1%29/2%7D%20%3D%5Csqrt%7B2%7D%20%5Cmbox%7Bcos%7D%20%5Cfrac%7B%5Cpi%7D%7B4%7D%282r%2B1%29.gif [Broken]

Here r is a positive integer.
3. The attempt at a solution

I verified this formula by inserting r=4k ~ 4k+3 (k=0,1,2....), but I still have no idea how to derive it from the left hand side of the equation.

Last edited by a moderator: May 5, 2017
2. Mar 2, 2012

HallsofIvy

I don't know what you mean by "r=4k ~ 4k+3" but the equation is clearly NOT true for n= 0, 1, 2, etc.

3. Mar 2, 2012

the_epi

http://www.wolframalpha.com/input/?i=%28-1%29^%28r%28r%2B1%29%2F2%29

go to derivate and click show steps.

4. Mar 2, 2012

j1221

Hello HallsofIvy,

Thank you very much for pointing out my mistake. I typed the wrong formula. I have corrected it. Would you please check it out again?

Thank you again.

5. Mar 2, 2012

j1221

Hello the_epi,

Thanks for your help. But I checked the website and check the Derivative part, I still do not understand how the Derivative related to the formula above. Could you please explain?

Thanks a lot.

6. Mar 2, 2012

HallsofIvy

For r a positive integer, 2r+ 1 is odd so, dropping multiples of $2\pi$, $cos(\pi/4(2r+1)$ is $cos(\pi/4)= \sqrt{2}/2$, $cos(3\pi/4)= -\sqrt{2}/2$, $cos(5\pi/4)= \sqrt{2}/2$, and $cos(7\pi/4)= -\sqrt{2}/2$. So what does the left side give? I would look at r= 4n, 4n+1, 4n+2, and 4n+ 3 and compare to those values.

7. Mar 2, 2012

j1221

Thank you very much HallsofIvy. I did the same thing to check this equation.

But I do not know how to DERIVE it. Do you have any ideas? Thanks!!

8. Mar 2, 2012

SammyS

Staff Emeritus
This formula holds only for r being an integer. Right ?

9. Mar 2, 2012

j1221

Yes!

10. Mar 3, 2012

SammyS

Staff Emeritus
Then $\displaystyle\cos\left(\frac{\pi}{4}(2r+1)\right)=\cos\left(\frac{\pi}{2}r+\frac{\pi}{4}\right)\,.$
Use the angle addition identity for the cosine.