Deriving Speed In Terms of Potential Difference

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SUMMARY

This discussion focuses on deriving speed in terms of potential difference (voltage) using fundamental physics equations. The key formula derived is v = √(2ΔVq/m), where v represents speed, ΔV is the potential difference, q is the charge, and m is the mass. The derivation utilizes principles of energy conservation, specifically ΔKE = qΔV, to establish the relationship between kinetic energy and electric potential energy. The discussion confirms that this approach is valid under the assumption of energy conservation.

PREREQUISITES
  • Understanding of basic physics concepts, particularly kinetic energy and potential energy.
  • Familiarity with the equation ΔKE = qΔV.
  • Knowledge of the relationship between force, work, and energy.
  • Basic algebra skills for manipulating equations.
NEXT STEPS
  • Explore the implications of energy conservation in electric fields.
  • Study the derivation of kinetic energy from potential energy in more complex systems.
  • Learn about the role of charge and mass in electric potential energy calculations.
  • Investigate real-world applications of speed derived from potential difference in electrical engineering.
USEFUL FOR

Students of physics, electrical engineers, and anyone interested in the relationship between electric potential and kinetic energy in physical systems.

Oriako
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I'm attempting to derive speed in terms of potential difference (voltage), can anyone let me know if there are any errors?

[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_k%3D%5Cfrac%7B1%7D%7B2%7D%5Ctext%7Bmv%7D%5E2.gif

[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2E_p%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_k%3DE_p.gif

[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%28%5Ctext%7Bma%24%5CDelta%20%24d%7D%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_p%3D%5Ctext%7Bmg%24%5CDelta%20%24h%7D%20.gif may be generalized to [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21E_p%3D%5Ctext%7Bma%24%5CDelta%20%24d%7D.gif for electric energy.

[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%5Cleft%28F_%7B%5Ctext%7Bnet%7D%7D%5Ctext%7B%24%5CDelta%20%24d%7D%5Cright%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21F_%7B%5Ctext%7Bnet%7D%7D%3D%5Ctext%7Bma%7D.gif

[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2W%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21W%3DF_%7B%5Ctext%7Bnet%7D%7D%5Ctext%7B%24%5CDelta%20%24d%7D.gif

[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%5Ctext%7B%24%5CDelta%20%24E%7D%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21%5Ctext%7B%24%5CDelta%20%24E%7D%20%3D%20W.gif

[PLAIN]http://www.texify.com/img/%5CLARGE%5C%21v%3D%5Csqrt%7B%5Cfrac%7B2%28%5Ctext%7B%24%5CDelta%20%24Vq%7D%29%7D%7Bm%7D%7D.gif, since [PLAIN]http://www.texify.com/img/%5CLARGE%5C%21%5Ctext%7B%24%5CDelta%20%24Vq%7D%3D%5Ctext%7B%24%5CDelta%20%24E%7D.gif

Therefore, speed is equal to the square root of double the product of charge and potential difference divided by mass.

Thanks!
 
Last edited by a moderator:
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Seems like that took a lot of work! If you accept conservation of energy, thus ΔKE = qΔV (ignoring signs), then you can get to the punchline in one step.
 
Sorry, forgot to mention it. But I did this to prove to myself that ΔE = E_k
 

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