Derivation of the differential Chapman-Kolmogorov Equation

  • Context: Graduate 
  • Thread starter Thread starter vancouver_water
  • Start date Start date
  • Tags Tags
    Derivation Differential
Click For Summary
SUMMARY

The discussion focuses on the derivation of the differential Chapman-Kolmogorov (CK) equation, specifically the form A(t)T(x,t|x',t') = ∂/∂t T(x_3,t_3|x_1,t_1). The integral equation T(x_3,t_3|x_1,t_1) is defined as the probability density of a Markov process. The user expresses confusion regarding the transition from a three-time parameter representation to a single time parameter in A(t). The referenced article "The Master Equation" on ScienceDirect highlights a simplified form of the CK equation, which may lead to different interpretations.

PREREQUISITES
  • Understanding of Markov processes and their properties
  • Familiarity with integral equations and differential equations
  • Knowledge of time translation operators in stochastic processes
  • Basic grasp of probability density functions
NEXT STEPS
  • Study the derivation of the differential Chapman-Kolmogorov equation in detail
  • Explore the properties of time translation linear operators in stochastic processes
  • Review the differences between various forms of the Chapman-Kolmogorov equation
  • Investigate the implications of the Master Equation in the context of Markov processes
USEFUL FOR

Researchers, mathematicians, and physicists working on stochastic processes, particularly those focused on Markov processes and the Chapman-Kolmogorov equation.

vancouver_water
Messages
76
Reaction score
10
TL;DR
I am following the book "The Theory of Open Quantum Systems" by Breuer and Petruccione. I can follow the derivation of the integral CK equation but do not understand their derivation of the differential CK equation.
The integral equation is T(x_3,t_3|x_1,t_1)=\int \text{d}x_2T(x_3,t_3|x_2,t_2)T(x_2,t_2|x_1,t_1) where T(x_3,t_3|x_1,t_1) is the probability density of a Markov process taking the value x_3 at time t_3 given that it took the value of x_1 at time t_1. So far so good. To derive the differential CK equation, they take the time derivative of the integral equation and the result is \frac{\partial}{\partial t}T(x,t|x',t')=A(t)T(x,t|x',t') where A(t) is time translation linear operator defined in terms of a density as A(t)\rho(x)=\lim_{\Delta t\rightarrow 0}\frac{1}{\Delta t}\int \text{d}x'[T(x,t+\Delta t|x',t)-\delta(x-x')]\rho(x'). I don't understand how to derive that form of A(t). What I would think (since they are differentiating w.r.t. the first time parameter) is that
\begin{align*}<br /> \frac{\partial}{\partial t_3}T(x_3,t_3|x_1,t_1) &amp;= \lim_{\Delta t\rightarrow 0}\frac{1}{\Delta t}\int \text{d}x_2[T(x_3,t_3+\Delta t|x_2,t_2)T(x_2,t_2|x_1,t_1)-T(x_3,t_3|x_2,t_2)T(x_2,t_2|x_1,t_1)] \\ &amp;= \lim_{\Delta t\rightarrow 0}\frac{1}{\Delta t}\int \text{d}x_2[T(x_3,t_3+\Delta t|x_2,t_2)-T(x_3,t_3|x_2,t_2)]T(x_2,t_2|x_1,t_1)]<br /> \end{align*}
but I cannot get this into the same functional form as what they get. They only have one time parameter in their A(t) but I still have all three time parameters.

What am I missing?

Thanks!
 
Physics news on Phys.org
vancouver_water said:
They only have one time parameter in their A(t) but I still have all three time parameters.

On https://www.sciencedirect.com/topics/mathematics/chapman-kolmogorov-equation the article "The Master Equation" gives equation 1.5 as a "simplified form" of the CK equation. It's actually a different equation since the variables are defined differently. Perhaps the book you are reading uses such an interpretation.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 27 ·
Replies
27
Views
4K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
23
Views
2K