Derivation of the Fokker-Planck Equation by Continuity

  • Context: Undergrad 
  • Thread starter Thread starter fayled
  • Start date Start date
  • Tags Tags
    Continuity Derivation
Click For Summary
SUMMARY

The Fokker-Planck equation is derived by enforcing the conservation of probability, leading to the expression ∂tp(x,t)=-∂x[p(x,t)v(x,t)]+∂x[D(x,t)∂xp(x,t)]. This derivation incorporates both convective and diffusive terms in the probability flux, represented as J=p(r,t)v(r,t)-D(r,t)∇p(r,t). The discrepancy between this form and the standard representation found on Wikipedia, which includes a second derivative term, is a point of inquiry for further clarification.

PREREQUISITES
  • Understanding of probability conservation principles
  • Familiarity with the Fokker-Planck equation
  • Knowledge of vector calculus and the divergence theorem
  • Basic concepts of diffusion and convection in physics
NEXT STEPS
  • Study the derivation of the Fokker-Planck equation in detail
  • Explore the implications of convective and diffusive terms in probability flux
  • Examine the divergence theorem and its applications in physics
  • Investigate the differences between various forms of the Fokker-Planck equation
USEFUL FOR

Mathematicians, physicists, and researchers in statistical mechanics who are interested in the derivation and applications of the Fokker-Planck equation.

fayled
Messages
176
Reaction score
0
Derive the Fokker-Planck equation by requiring conservation of probability:
∂VJ⋅dS=-d/dt∫Vp(r,t)dV
The flux can be written as a sum of convective and diffusive terms
J=p(r,t)v(r,t)-D(r,t)p(r,t)
and substitution of this with use of the divergence theorem yields
tp(x,t)=-∂x[p(x,t)v(x,t)]+∂x[D(x,t)∂xp(x,t)]
where I have moved to one dimension for simplicity.

However the form found here
https://en.wikipedia.org/wiki/Fokker–Planck_equation
is given as
tp(x,t)=-∂x[p(x,t)v(x,t)]+∂x2[D(x,t)p(x,t)]

I was wondering if anybody would be able to help me account for this difference. Thanks!
 
Physics news on Phys.org
You might have better luck in a math forum.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 53 ·
2
Replies
53
Views
3K
  • · Replies 19 ·
Replies
19
Views
3K