Derivation of Time Dependent Schrodinger Equation

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The discussion centers on a specific step in the derivation of the time-dependent Schrödinger equation, as outlined in "Quantum Mechanics: The Theoretical Minimum." Peter Yu seeks clarification on a calculation involving the expression (I+iε H†)(I-iε H) and its simplification. A key point is the neglect of the ε² term, which allows for division by iε to achieve the desired result. Shyan provides assistance, confirming the approach and helping Peter understand the derivation. The exchange highlights the collaborative nature of problem-solving in quantum mechanics discussions.
Peter Yu
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Hi All,
I have problem in understanding one step in the derivation of the time dependent Schrodinger Equation. Please see attached file page 2 (marked in red). Most grateful if someone can help!
Peter Yu
(This is from Quantum Mechanics The Theoretical Minimum Page 99-102)
 

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## (I+i\epsilon H^\dagger)(I-i\epsilon H)=I \Rightarrow I-i\epsilon H+i\epsilon H^\dagger +\epsilon^2H^\dagger H =I \Rightarrow -i\epsilon H+i\epsilon H^\dagger +\epsilon^2H^\dagger H =0##
Now if you ignore the ##\epsilon^2## term and divide by ##i\epsilon##, you get what you're after.
 
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Hi Shyan,
Many Many thank for your help!
Regards,
Peter Yu
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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