SUMMARY
The derivative of the function arctan(x - sqrt(1+x^2)) is calculated using the chain rule. The substitution u = x - sqrt(1+x^2) leads to dy/du = 1/(1 + u^2), which simplifies to dy/du = 1/(1 + (x - sqrt(1+x^2))^2). The derivative du/dx is found to be 1 - (x/(sqrt(1+x^2))). The final expression for dy/dx is (1/(1 + (x - sqrt(1+x^2))^2)) * (1 - (x/(sqrt(1+x^2}))).
PREREQUISITES
- Understanding of the chain rule in calculus
- Familiarity with derivatives of inverse trigonometric functions
- Knowledge of algebraic manipulation involving square roots
- Basic proficiency in calculus notation and simplification techniques
NEXT STEPS
- Practice finding derivatives of other inverse trigonometric functions
- Study the application of the chain rule in more complex functions
- Explore simplification techniques for expressions involving square roots
- Learn about the graphical interpretation of derivatives of arctan functions
USEFUL FOR
Students studying calculus, mathematics educators, and anyone looking to enhance their understanding of derivatives involving inverse trigonometric functions.