Derivative. arctan(x - sqrt(1+x^2))

  • Thread starter Thread starter smith007
  • Start date Start date
  • Tags Tags
    Derivative
Click For Summary
SUMMARY

The derivative of the function arctan(x - sqrt(1+x^2)) is calculated using the chain rule. The substitution u = x - sqrt(1+x^2) leads to dy/du = 1/(1 + u^2), which simplifies to dy/du = 1/(1 + (x - sqrt(1+x^2))^2). The derivative du/dx is found to be 1 - (x/(sqrt(1+x^2))). The final expression for dy/dx is (1/(1 + (x - sqrt(1+x^2))^2)) * (1 - (x/(sqrt(1+x^2}))).

PREREQUISITES
  • Understanding of the chain rule in calculus
  • Familiarity with derivatives of inverse trigonometric functions
  • Knowledge of algebraic manipulation involving square roots
  • Basic proficiency in calculus notation and simplification techniques
NEXT STEPS
  • Practice finding derivatives of other inverse trigonometric functions
  • Study the application of the chain rule in more complex functions
  • Explore simplification techniques for expressions involving square roots
  • Learn about the graphical interpretation of derivatives of arctan functions
USEFUL FOR

Students studying calculus, mathematics educators, and anyone looking to enhance their understanding of derivatives involving inverse trigonometric functions.

smith007
Messages
9
Reaction score
0

Homework Statement



Find the derivative of the function. Simplify where possible.
arctan(x - sqrt(1+x2))

Homework Equations



Chain rule

The Attempt at a Solution



let u = x - sqrt(1+x2)

y = tan-1(u)

dy/du = 1/(1+ u2)
sub in u.
dy/du = 1/1 + (x - sqrt(1+x2))2


du/dx = 1 - 1/2 (1+x2)-1/2 (2x)

dy/dx = (1/1 + (x - sqrt(1+x2))2) (1 - 1/2 (1+x2)-1/2 (2x))


I always seem to forget 1 term and I am basically wondering if my method here is correct.
 
Physics news on Phys.org
Looks right to me. It would be good to include another pair of parentheses in the first term:

dy/dx = (1/(1 + (x - sqrt(1+x2))2)) (1 - 1/2 (1+x2)-1/2 (2x))
 
Thank you.

I am new to the forums here and I must say they are great!
 
You're welcome, and welcome to PF.
 

Similar threads

Replies
4
Views
2K
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
3
Views
2K
  • · Replies 105 ·
4
Replies
105
Views
7K
  • · Replies 12 ·
Replies
12
Views
3K
Replies
19
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K