Derivative of 2x^2.9 - 3x^3.4 + 19

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JayDub
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if y = 2x^2.9 - 3x^3.4 + 19

the derivative?
y' = 2(2.9)x ^ 1.9 -3(3.4)x^2.4 + 0
y' = 5.8x^1.9 - 10.2x^2.4
 
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and then the y'' of that would be...

y'' = 11.02x^0.9 - 24.48x^1.4?