Derivative of d'Alambert operator?

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SUMMARY

The discussion centers on the differentiation of the d'Alembert operator, specifically the expression \(\partial_{\mu}\Box\phi\), where \(\Box\) is defined as \(\partial^{\mu}\partial_{\mu}\). It is clarified that the d'Alembertian of a scalar field results in a scalar, and differentiating this scalar yields a vector. Therefore, the expression \(\partial_\nu \Box \phi = \partial_\nu (\partial^\mu \partial_\mu \phi)\) does not equal zero identically.

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Dixanadu
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Hi guys,

So I've ended up in a situation where I have \partial_{\mu}\Box\phi. where the box is defined as \partial^{\mu}\partial_{\mu}. I'm just wondering, is this 0 by any chance...?

Thanks!
 
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You shouldn't use same greek letters. Because the d'Alembertian of a scalar field is a scalar and when you differentiate that, you'll get a vector. So you should write \partial_\nu \Box \phi=\partial_\nu (\partial^\mu \partial_\mu \phi). I don't see a reason that makes it zero identically!
 

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