Derivative of e^(t^2) with respect to t

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SUMMARY

The derivative of e^(t^2) with respect to t is calculated using the Chain Rule, resulting in the expression e^(t^2) * 2t. A discussion participant, Kev, confirmed this result using Maple, which provided the equivalent expression 2 * e^(t^2) * ln(e). The clarification that ln(e) equals 1 indicates that both expressions are mathematically identical. This reinforces the understanding that the Chain Rule effectively applies to exponential functions.

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Homework Statement


Find the derivative of e^(t^2) with respect to the variable t.


Homework Equations


Chain Rule


The Attempt at a Solution


Using chain rule, the answer should be e^(t^2)*2t, but when I used Maple to confirm my answer, the solution is 2*e^(t^2)*t*ln(e).
My train of thought starts by thinking of the exponential as e^x (where x = t^2), then I apply the chain rule on the exponents of e, so I get 2t; thus, giving me the solution e^(t^2)*2t.

Thanks in advance.
Kev
 
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It is the same thing since ln(e)=1.

Maple gave that answer because the derievative of a^{x} is a^{x}lna.
 

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