Derivative of e^y: Solving w/ Chain Rule

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Homework Statement



What is the derivative of e^y? i think i am differentiating with respect to x

Homework Equations



Derivative of y^x is y^x

The Attempt at a Solution



I don't know if I should use the chain rule or treat it like y^x. When i used the chain rule I got ye^y-1, but then I wondered if it should be e^y.
 
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The derivative with respect to y? Then sure, d/dy(e^y)=e^y. You can't use the power law d/dy(y^n)=n*y^(n-1). In one the variable y is an exponent, in the other it's not. They are very different functions.
 
brambleberry said:

Homework Statement



What is the derivative of e^y? i think i am differentiating with respect to x



Homework Equations



Derivative of y^x is y^x

The Attempt at a Solution



I don't know if I should use the chain rule or treat it like y^x. When i used the chain rule I got ye^y-1, but then I wondered if it should be e^y.
I don't see what y^x has to do with your original equation. y^x is not anything like e^y and yes, you should use the chain rule. But the chain rule does NOT give "ye^{y-1}"!

The chain rule says that
\frac{d e^y}{dx}= \frac{de^y}{dy}{dy}{dx}
\frac{d e^y}{dy}
is e^y, NOT "ye^{y-1}". That power formula only applies to the variable to a constant power, not a constant power to a variable power.

\frac{de^y}{dx}= \frac{de^y}{dy}\frac{dy}{dx}= e^y\frac{dy}{dx}[/itex]
 

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