Derivative of Force and Work in Respect to Time

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Homework Help Overview

The discussion revolves around the relationship between force, work, and their derivatives with respect to time. Participants explore concepts from mechanics, particularly focusing on how these quantities interact and the implications of time-dependent forces.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants examine the derivative of force with respect to time and its relation to work, questioning if it equates to work done over time. There are discussions on the definitions of work and power, and whether force can depend on time.

Discussion Status

The conversation is ongoing, with various interpretations being explored. Some participants provide insights into the definitions of work and power, while others express confusion regarding the implications of time-dependent forces. There is no explicit consensus, but several productive lines of reasoning are being developed.

Contextual Notes

Participants note that the definitions and relationships discussed may change based on whether forces are time-dependent or independent. There is also mention of specific references to textbooks that may influence the understanding of these concepts.

  • #31
marlon said:
Indeed that is what i meant. Don't mind dextercioby with his useless remarks. He is just angry and not willing to see he's just regurgitating self-adapted physics...

let's not get into that...

YOU ARE RIGHT...

marlon

:smile: I'm not angry... :-p For the last couple of days,i've been laughing my a$$ out... :smile: I ain't got nobody to be angry at...If somebody proves me wrong,i'll accept it,even if it's Marlon... :-p So far,i haven't had sufficient evidence to admit i was/am/will be wrong...

Self-adapted physics u say... :-p I wish i could believe you... :-p

Daniel.
 
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  • #32
dextercioby said:
:smile: I'm not angry... :-p For the last couple of days,i've been laughing my a$$ out... :smile: I ain't got nobody to be angry at...If somebody proves me wrong,i'll accept it,even if it's Marlon... :-p So far,i haven't had sufficient evidence to admit i was/am/will be wrong...

Self-adapted physics u say... :-p I wish i could believe you... :-p

Daniel.

good for you...

marlon
 
  • #33
dextercioby said:
This is wrong,if 'W' stands for potential energy.If it stands for work,then the force should not depend on time:
\frac{dW}{dt}=\frac{d}{dt}(\vec{F}\cdot \vec{r})=\vec{F}\cdot \vec{v}=P(1)
,where P is the mechanical power.

this is just plain wrong again...

\Delta W = \int mvdv = \Delta E _{kinetic}

from this formula you need to start...

marlon
 

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