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I was wondering whether it is possible or not to find a functionf:ℝ→ℝ, such that its first derivative is equal to its square: [tex]f'(x)=f(x)^2[/tex]

It is known that if we replace the exponent 2 with 1, and require that [itex]f'(x)=f(x)[/itex], then a solution would be [itex]f(x)=e^x[/itex], but when we require the derivative to be equal to the functionsquared, the solution (if it exists at all) is less obvious.

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# Derivative of function = square of the function?

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