Derivative of ln3: Simple Problem Solution

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Homework Statement


ln (2x^2 + 3)


Homework Equations


ln 2x^2 + ln 3


The Attempt at a Solution


(4x/2x^2) + (3/3)
(2x/x^2) + 1

I know this is a simple problem but what is the derivative of ln3? Is it 1 (3/3) or 0?
 
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properties of logs

[tex]\ln(ab)=\ln(a)+\ln(b)[/tex]

what you have is

[tex]\ln(a+b)=\ln(a+b)[/tex]

example

[tex]\ln(x^{2}+3)[/tex]

differentiating

[tex]\frac{2x}{x^{2}+3}[/tex]
 
Last edited:
rocophysics said:
example

[tex]\ln(x^2)[/tex]

differentiating

[tex]\frac{2x}{x^2}[/tex]

properties of logs

[tex]\ln(ab)=\ln(a)+\ln(b)[/tex]
Can't you distribute the ln to get lna + lnb? I don't know what the derivative of ln3 is? Is it 3/3 or 0/3.
 
BuBbLeS01 said:
Can't you distribute the ln to get lna + lnb? I don't know what the derivative of ln3 is? Is it 3/3 or 0/3.
i just updated my post, i clicked submit on accident while trying to preview.
 
Oh okay I see now. So it would be...
(4x)/(2x^2 + 3)
(2x)/(x^2 + 3)