Derive an expression for the applied field of a superconducting wire

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SUMMARY

The discussion focuses on deriving an expression for the applied magnetic field in a superconducting wire using the equation ##\vec{B} = \mu_0 \vec{H}##. The contributor calculates critical current density (i_c) and current density (j_c) based on the applied magnetic field (H) and wire radius (r), leading to the expression for magnetic field (B) as ##B = \mu_0 \frac{r j_c}{2}##. The contributor expresses uncertainty regarding the mathematical approach and the rationale behind dividing by the entire cross-section of the wire, questioning the flow of current and its impact on the internal magnetic field.

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Homework Statement
A piece of superconducting wire of length l and radius r is made from a material of critical current density ##j_c##. It is placed in a magnetic field ##B## which is applied parallel to the axis of the wire. The magnetic moment m is measured as B increases from zero up to a maximum ##B_{max}## and back again to zero. If a supercurrent flows in a thin layer of thickness ##\lambda## at the surface of the wire, derive an expression for the applied field at which the moment m changes discontinuously. You may assume that l >> r.
Relevant Equations
##\vec{B} = \mu_0 \vec{H}##
##\oint \vec{H}\cdot d\vec{l} = i_c##
So far the best I've been able to come up with is to use ##\vec{B} = \mu_0 \vec{H}## which gives me
i_c = H 2\pi r
j_c = \frac{H 2\pi r}{\pi r^2} = \frac{2H}{r}
\therefore B = \mu_0 \frac{r j_c}{2}
I'm fairly confident this is just terrible math and physics on my behalf but I'm struggling to see how to relate all the given variables into one unifying equation/
 
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Why do you divide by the whole cross section? Current will only flow close to the boundary.

Did you draw a sketch? Where is current is flowing in which direction to make the internal field zero?
 

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