Deriving an equation for water flowing from a tap

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Homework Help Overview

The problem involves deriving equations related to the flow of water from a tap, specifically focusing on the speed of the water as it falls and the relationship between its cross-sectional areas at two points. The subject area includes fluid dynamics and kinematics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of kinematic equations and the continuity equation to derive expressions for the speed of water as it falls. There are attempts to express the speed in terms of height and cross-sectional areas. Questions arise regarding the interpretation of variables and the physical meaning of terms like A1v1.

Discussion Status

The discussion is ongoing, with participants providing guidance on the derivation steps and questioning the completeness of the information provided. There is acknowledgment of missing data, specifically the height difference between the two points, which may affect the ability to calculate numerical values.

Contextual Notes

Participants note that the problem may require leaving answers in terms of variables due to the lack of specific numerical data for the height difference between A1 and A2.

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Homework Statement


A stream of water flows downward from a tap. Assume that the water is in free fall once it leaves the tap, at which point its speed is v1, and the initial diameter of the water stream is A1.
(i) Find an expression for the speed v2 of the liquid as a function of the distance, h, it has fallen.
(ii) Combine this with the equation of continuity, to find an expression for the speed v2 in terms of the distance h and the cross-sectional areas at A1 and A2.
(iii) The cross-sectional area of the stream changes from 1.2 cm2 to 0.35 cm2 between the positions A1 and A2. Calculate the volume rate of flow of water from the tap, in cm3 s

Homework Equations


Continuity equation
Kinematic equations

The Attempt at a Solution


(i)

.5(v1)2 + gh = .5(v2)2
therefore v2 = √(2*(.5(v1)2)+gh)

(ii)
.5(v1)2 + gh = .5(v2)2

therefore using A1v1 = A2v2

.5(v1)2 + gh = .5(v1)2*A1/A2

and so
.5(v1)2((A1/A2)2 - 1) = gh

therefore v1 = √(2gh/(A1/A2)2 - 1)

(iii)
I'm not sure how you can get a numerical value for this question but the question seems to imply you can.

any help would be appreciated.
 
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Woolyabyss said:
.5(v1)2 + gh = .5(v2)2
therefore v2 = √(2*(.5(v1)2)
Try that step again.
Woolyabyss said:
therefore v1 = √(2gh/(A1/A2)2 - 1)
It asks for v2 in terms of h, A1, A2, not for v1.

Your continuity equation involved terms like A1v1. What physical aspect does that represent?
 
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haruspex said:
Try that step again.

It asks for v2 in terms of h, A1, A2, not for v1.

Your continuity equation involved terms like A1v1. What physical aspect does that represent?

Ok, so

v2 = (2gh/(1-(A2/A1)^2))^.5

A1v1 represents the volume flow rate
 
Woolyabyss said:
Ok, so

v2 = (2gh/(1-(A2/A1)^2))^.5

A1v1 represents the volume flow rate
Yes, you seem to be missing a piece of data. E.g. the height difference between A1 and A2. Is there any more info, maybe in a diagram?
 
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haruspex said:
Yes, you seem to be missing a piece of data. E.g. the height difference
haruspex said:
Yes, you seem to be missing a piece of data. E.g. the height difference between A1 and A2. Is there any more info, maybe in a diagram?

between A1 and A2. Is there any more info, maybe in a diagram?

There is a diagram but it doesn't contain anymore information. I guess you're meant to leave your answer in terms of h.
 
Woolyabyss said:
There is a diagram but it doesn't contain anymore information. I guess you're meant to leave your answer in terms of h.
Maybe, but it seems odd to provide numbers for the areas but not for h.
 

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