Solving for Air Speed in an Air Duct

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SUMMARY

The discussion focuses on calculating the air speed in a cylindrical air duct with a radius of 15 cm, designed to replenish air in a room measuring 10 m x 6 m x 3 m every 10 minutes. Using the equation A1V1 = A2V2, the area of the duct (A1) is calculated as 706.5 cm². To determine the necessary air speed (V1) to achieve the required volumetric flow rate, participants must first calculate the room's volume and the corresponding flow rate needed to replace that volume within the specified time frame.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically volumetric flow rate.
  • Familiarity with the area and volume calculations for cylindrical shapes.
  • Knowledge of the continuity equation in fluid mechanics.
  • Basic algebra skills for solving equations.
NEXT STEPS
  • Calculate the volume of the room using the formula for rectangular prisms.
  • Determine the required volumetric flow rate in cubic meters per second.
  • Learn how to convert units from cubic centimeters to cubic meters for consistency.
  • Explore the implications of duct size and shape on air speed and flow efficiency.
USEFUL FOR

Engineers, HVAC professionals, and students studying fluid dynamics or air flow systems will benefit from this discussion, particularly those involved in designing air circulation systems.

TooDank4U
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Homework Statement


A 15 cm. radius cylindrical air duct is used to replenish the air of a room 10 m.*6 m.* 3m. Every 10 minutes. Determine the speed of the air through the duct in m/s. A1=15 V1=? A2=19 V2=0

Homework Equations


A1V1=A2V2

The Attempt at a Solution


3.14*15^2 * ?= 19*0=. 3.14*15^2=706.5
 
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Your attempt makes no sense. show units and explain your reasoning.

What is the volume of the room?
What volume per second must flow through the room to replace that volume every ten minutes?
To achieve that volumetric flow rate how fast must that air flow through the duct?
 
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