Deriving inverse tans from complex product?

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Discussion Overview

The discussion revolves around deriving the expression \( 4\,\arctan \left( 1/5 \right) -\arctan \left( {\frac {1}{239}} \right) \) from the complex product of \( \left( 1+i \right) \left( 5-i \right) ^{4} \). Participants explore the relationship between the argument of the complex expression and the arctangent functions involved, focusing on the mathematical approach to the derivation.

Discussion Character

  • Exploratory
  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant notes the established relationship between the argument of the complex product and the arctangent functions, stating it as \( \frac{\pi}{4} - 4\arctan \frac{1}{5} \).
  • Another participant suggests expanding the product using the binomial theorem, although they express that it may be cumbersome, proposing an alternative method of squaring \( 5-i \) and multiplying by \( 1+i \).
  • A later reply provides the result of the expansion as \( 956-4i \) and calculates the argument, leading to \( -\arctan (1/239) \), which they find interesting.
  • One participant reflects on the complexity of multiplication in this context, contrasting it with their understanding of polar form.
  • Another participant mentions that this derivation relates to Machin's formula for pi, indicating a historical connection.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the best approach to the derivation, and multiple methods are discussed without resolution. The relationship to Machin's formula is noted but not universally agreed upon as the main focus of the discussion.

Contextual Notes

The discussion involves assumptions about the properties of complex numbers and the arctangent function, but these are not fully explored or defined. The steps in the derivation are not completely resolved, leaving some mathematical details open to interpretation.

rsnd
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I am supposed to derive [itex]4\,\arctan \left( 1/5 \right) -\arctan \left( {\frac {1}{239}}<br /> \right)[/itex] from the complex product of [itex]\left( 1+i \right) \left( 5-i \right) ^{4}[/itex] I do see how the argument of product of the complex expression is equal to pi/4 - 4 arctan(1/5) but I am totally lost. SO how am I supposed to approach this? Thanks heaps in advance.
 
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Well You have to equate to long way and the short way :D

You already established that the argument to the complex product is [itex]\frac{\pi}{4} -4\arctan \frac{1}{5}[/itex]

What you had to do next is have the pleasure of EXPANDING YOUR PRODUCT. Binomial theorem is just too much of a hassle this time. Write the product as
[tex](5-i)^{2^2}\cdot(1+i)[/tex]. So just square 5-i, 2 times, and multiply that by 1+i.

FUN FUN, I did it for you :P You get : 956-4i . The argument of this is arctan (-4/956)= - arctan (1/239) . Isn't that interesting?
 
And here I thought I'd never have to multiply the hard way after learning the polar form. Thanks heaps again =)
 

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