Deriving Maxwell's Relation with Thermodynamic Variables

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Homework Help Overview

The discussion revolves around deriving a specific relation involving thermodynamic variables, particularly focusing on Maxwell's relation and its implications in the context of temperature, volume, and entropy.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the relationship between differentials of temperature and heat capacity, with some questioning the meaning of these differentials and their relevance to the problem. There is an attempt to connect the equation to known thermodynamic identities.

Discussion Status

The discussion is ongoing, with participants providing suggestions for approaches, such as writing out differentials. However, there is no consensus on how to proceed, and some participants express confusion regarding the terminology and methods being discussed.

Contextual Notes

There appears to be a lack of clarity regarding the definitions and relationships between the variables involved, particularly concerning the derivatives and their respective variables.

mdwerner
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Homework Statement


Derive the following general relation : [tex]\left(\frac{\partial T}{\partial V}\right)_{S} = - \frac{1}{C_{V}} T \left(\frac{\partial p}{\partial T}\right)_{V}[/tex]


Homework Equations


Maxwell's Relation : [tex]\left(\frac{\partial T}{\partial V}\right)_{S} = - \left(\frac{\partial p}{\partial S}\right)_{V}[/tex]


The Attempt at a Solution



The similarity of the question to the maxwell's relation is the only thing I could recognize - but I don't see what to do? Any suggestions will be appreciated.
 
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First try writing out the differentials for T and 1/Cv to see if that gives you any inspiration.
 


I don't understand, what do you mean by the differentials of T and 1 / CV ? A derivative? if so, with respect to what?
One thing I had considered would be to multiply this function by [tex]\frac{\partial S}{\partial T}[/tex] but that seems to jumble the left side of the equation...
 


T is [tex]\frac{\partial U}{\partial S}[/tex]

and

1/Cv is [tex]\frac{\partial T}{\partial U}[/tex]
 

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