Deriving Partial Derivatives for Power Functions

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SUMMARY

The discussion focuses on deriving the partial derivative ∂f(x,y)/∂x for the function f(x,y) = g(x,y)h(x,y). The derivation utilizes the logarithmic differentiation method, where ln(f(x)) = h(x)ln(g(x)). The final expression for the derivative is ∂f/∂x = g(x)^{h(x)}(ln(g(x))∂h/∂x + (h(x)/g(x))∂g/∂x). This method applies when both g and h are functions of x and y, treating y as a constant during differentiation.

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BobV
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Is there a derivation for ∂f(x,y)/∂x given:

f(x,y): g(x,y)h(x,y)

e.g. sin(x)(x+2y)
 
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Yes, of course. Given [itex]f(x)= g(x)^{h(x)}[/itex] we have [itex]ln(f(x))= h(x)ln(g(x))[/itex], then [itex]\frac{1}{f(x)}\frac{df}{dx}= ln(g(x))\frac{dh}{dx}+ \frac{h(x)}{g(x)}\frac{dg}{dx}[/itex]

So [tex]\frac{df}{dx}= g(x)^{h(x)}\left(ln(g(x))\frac{dh}{dx}+ \frac{h(x)}{g(x)}\frac{dg}{dx}\right)[/tex]

Of course, the same is true if g and h are functions of x and y and you are taking the derivative with respect to x because you are treating y as a constant.

(This has nothing to do with differential equations.)
 
Thanks

Ah, I got it, I see what you did! Sometimes when puzzled in an instant with mysterious delight the answer appears. Thanks for the surprise gift - and problem solution.
 

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