Partial Derivative: Correct Formulation?

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Discussion Overview

The discussion revolves around the correct formulation of the partial derivative of the product of two functions, specifically examining the expressions for ##\frac{\partial }{\partial x}u(x,y)v(x,y)##. Participants explore the definitions and limits involved in calculating these derivatives.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Some participants assert that the initial formulation of the partial derivative as a difference quotient is incorrect, emphasizing that it should be expressed as a limit.
  • Others propose that the correct formulation involves the limit definition of the partial derivative, specifically stating it as $$\lim_{h \to 0}\frac{u(x+h, y)v(x+h, y) - u(x, y)v(x,y )}{h}$$.
  • There is a suggestion that using the product rule for partial derivatives leads to a different expression, which some participants attempt to reformulate as $$\frac{u(x+dx,y)-u(x,y)}{dx}v(x,y)+u(x,y)\frac{v(x+dx,y)-v(x,y)}{dx}$$.
  • Participants note that the reformulated expressions still need to incorporate limits to be correct.
  • A later reply indicates that both post 2 and post 4 are correct in their own contexts, suggesting a relationship between the two formulations.
  • One participant questions the meaning of "x + dx," implying a need for clarity regarding the notation and its implications in the context of non-standard analysis.

Areas of Agreement / Disagreement

Participants do not reach a consensus on a single correct formulation, as multiple interpretations and approaches are presented. There is acknowledgment that both post 2 and post 4 can be seen as correct under different contexts.

Contextual Notes

Limitations include the need for clarity on the use of limits in the definitions of partial derivatives and the implications of using non-standard analysis in the discussion.

Apashanka
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If given a function ##u(x,y) v(x,y)## then is it correct to write ##\frac{\partial }{\partial x}u(x,y)v(x,y)=\frac{u(x+dx,y)v(x+dx,y)-u(x,y)v(x,y)}{dx}##??
 
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Apashanka said:
If given a function ##u(x,y) v(x,y)## then is it correct to write ##\frac{\partial }{\partial x}u(x,y)v(x,y)=\frac{u(x+dx,y)v(x+dx,y)-u(x,y)v(x,y)}{dx}##??
Not quite. Above, you're using the definition of the (partial) derivative of the product of two functions, which is a limit.

Corrected, this would be $$\lim_{h \to 0}
\frac{u(x+h, y)v(x+h, y) - u(x, y)v(x,y )}{h}$$
 
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Mark44 said:
Not quite. Above, you're using the definition of the (partial) derivative of the product of two functions, which is a limit.

Corrected, this would be $$\lim_{h \to 0}
\frac{u(x+h, y)v(x+h, y) - u(x, y)v(x,y )}{h}$$
Ok using ##\frac{\partial}{\partial x}u(x,y)v(x,y)=\frac{\partial u(x,y)}{\partial x}v(x,y)+u(x,y)\frac{\partial v(x,y)}{\partial x}## can't it be ##\frac{u(x+dx,y)-u(x,y)}{dx}v(x,y)+u(x,y)\frac{v(x+dx,y)-v(x,y)}{dx}??##
 
Apashanka said:
Ok using ##\frac{\partial}{\partial x}u(x,y)v(x,y)=\frac{\partial u(x,y)}{\partial x}v(x,y)+u(x,y)\frac{\partial v(x,y)}{\partial x}## can't it be ##\frac{u(x+dx,y)-u(x,y)}{dx}v(x,y)+u(x,y)\frac{v(x+dx,y)-v(x,y)}{dx}??##
Again, not quite -- you are trying to use the definitions of the two partial derivatives without including that these are limits.

The corrected version would be $$\lim_{h \to 0}\left(\frac{u(x+h,y)-u(x,y)}{h}\right) v(x,y)+u(x,y)\lim_{h \to 0}\left(\frac{v(x+h,y)-v(x,y)}{h}\right)$$
 
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Mark44 said:
Again, not quite -- you are trying to use the definitions of the two partial derivatives without including that these are limits.

The corrected version would be $$\lim_{h \to 0}\left(\frac{u(x+h,y)-u(x,y)}{h}\right) v(x,y)+u(x,y)\lim_{h \to 0}\left(\frac{v(x+h,y)-v(x,y)}{h}\right)$$
So which is correct post 2 or post 4
 
Apashanka said:
So which is correct post 2 or post 4
Both are correct. It's possible to derive what I wrote in post 4 from what is in post 2.
 
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When you write "u(x+ dx)" exactly what do you mean by "x+ dx"? In order to make sense of that you would have to use "non-standard analysis" and I don't think that's what you mean.
 

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