Deriving the formula from a graph

  • Thread starter adjacent
  • Start date
  • #1
adjacent
Gold Member
1,553
63
So,here we have a graph.For every unit of 1(x axis),the unit of the previous y axis is multiplied.
Like this.
(0,2),(1,4),(2,8),(3,16)........
I don't know how the formula will be,and had never seen this kind of graph.
The y seems to be a geometric sequence,on which we can use, ## ar(n-1) ## .r is 2.a is 2
So 2 x 2(n-1)
n is the value of x.For every value of x,we can now find the value of y.
So how can we find the general formula of the graph?Is it ## y=2 x 2(x-1) ## ? I don't think so,If the x values started with 1,it's possible.

I don't know why LaTeX is not working,Help please.
 
Last edited:

Answers and Replies

  • #2
LCKurtz
Science Advisor
Homework Helper
Insights Author
Gold Member
9,559
770
Your pairs are ##(n, 2^{n+1})## for ##n=0,1,2,...##.
 
  • #3
adjacent
Gold Member
1,553
63
How did you derive that?What could be the general formula? ##y=2^{x+1}## ?
 
  • #4
LCKurtz
Science Advisor
Homework Helper
Insights Author
Gold Member
9,559
770
Your pairs are ##(n, 2^{n+1})## for ##n=0,1,2,...##.

How did you derive that?What could be the general formula? ##y=2^{x+1}## ?

Yes. You already noticed the ##y## values were powers of ##2##. So it was just a matter of adjusting the exponent to make the ##y## value agree with the ##x## value.
 
  • Like
Likes 1 person
  • #5
adjacent
Gold Member
1,553
63
Thanks, (lol I take reliable and cheap)
 

Related Threads on Deriving the formula from a graph

  • Last Post
Replies
3
Views
5K
Replies
23
Views
9K
  • Last Post
Replies
11
Views
2K
Replies
5
Views
3K
Replies
4
Views
6K
  • Last Post
Replies
1
Views
1K
Replies
3
Views
1K
  • Last Post
Replies
5
Views
2K
Top