Deriving the Wheatstone Bridge Equation with Respect to R3 - Math Nerd Help

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SUMMARY

The discussion focuses on deriving the Wheatstone bridge equation with respect to the resistor R3, specifically the equation VO=((R3/(R2+R3))-(R4/(R1+R4)))VS. A participant incorrectly derived the derivative as dVO/dR3 = ((1/(R2+R3))-(R3/(R2+R3)²))VS. The conversation also suggests setting R1 equal to R3 for further derivation and introduces a separate derivative problem involving y=((x/(12+x))-(4/(12+4)))·6.

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mhrobson
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I need to derive the following equation with respect to R3. This is the equation for a Wheatstone bridge. Unfortunately I am not very good at derivations. Here is the equation:
VO=((R3/(R2+R3))-(R4/(R1+R4)))VS

I came up with the following answer but was told that it is wrong:
dVO/dR3 = ((1/(R2+R3))-(R3/(R2+R3)2)VS

If you want to be a real sport, set R1=R3 and derive the same expression.
 
Physics news on Phys.org
Suppose [tex]y=((x/(12+x))-(4/(12+4)))\cdot 6[/tex], can you do dy/dx now?
 

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