Deriving a balanced bridge equation

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SUMMARY

The discussion centers on deriving the equation for V_5 in a balanced bridge circuit. The user initially applied a Delta-Wye transformation but encountered difficulties in simplifying the resulting equation. The solution provided indicates that the bridge is balanced when the ratio R1/R2 equals R3/R4, which can be demonstrated by setting V2 equal to V4, leading to no current across R5. This approach simplifies the problem significantly compared to the initial method attempted.

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  • Understanding of Delta-Wye transformations in circuit analysis
  • Familiarity with Ohm's Law and its applications
  • Basic knowledge of electrical circuits and bridge configurations
  • Ability to manipulate and simplify algebraic equations
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  • Study Delta-Wye transformation techniques in circuit analysis
  • Learn about balanced bridge conditions in electrical circuits
  • Explore advanced circuit simplification methods
  • Review Ohm's Law applications in various circuit configurations
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Electrical engineering students, circuit designers, and anyone involved in analyzing or designing balanced bridge circuits.

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I am having trouble finishing this problem. I am supposed to first derive an equation for V_5 in this circuit:

http://img292.imageshack.us/img292/599/picture3qy2.png

I applied a Delta-Wye transformation to get here:

http://img292.imageshack.us/img292/9672/workot8.jpg

From there I am supposed to show that the circuit is balanced when R1/R2 = R3/R4 for any value of R5. This is where I'm getting stuck. My attempt starts by setting the V5 equation equal to zero and then trying to reduce it. This isn't working very well since the V5 equation is pretty messy to begin with.

Am I going about this correctly, or is there an easier method I should use? Thanks for your help.
 
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Yes, I think the V5 equation is messy. But there's an easier way to show the condition for a balanced bridge.

The bridge is balanced if V2 = V4 since there will be no current then across R5. This also means V1 = V3. Then, from applying Ohm's law to the 2 equations and canceling the currents, you should get R1/R2 = R3/R4 quite easily.
 

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